Question

1. A metabolic reaction A↔ B has ∆G°’ = 7.5 kJ/mol This metabolic reaction takes place...

1. A metabolic reaction A↔ B has ∆G°’ = 7.5 kJ/mol This metabolic reaction takes place in solution in the human body and there are no solids or gases involved. a) Calculate Keq for the reaction at 25°C b) Calculate ∆G for the reaction at 37°C, when [A] = 0.5 mM and [B] = 0.1 mM. Is the reaction spontaneous under these conditions? c) How can the reaction’s direction in the cell be changed without changing the temperature? Be logical and explicit. In principle there are three different ways of doing this.

Homework Answers

Answer #1

At constant temperature, the reaction's direction in the cell be changed by changing the concentration of either reactant or product according to Lechetllier's principle.

If we increase the concentration of A, then there will be more reactant then the uxn moves foreward to the product side

At constant temperature, the reaction's direction in the cell be changed by changing the concentration of either reactant or product according to Lechetllier's principle.

If we increase the concentration of A, then there will be more reactant then the uxn moves foreward to the product side

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. For the reaction A(g) + 2B(g) ↔ 2C(g) ΔGo = −30.6 kJ. What is the...
1. For the reaction A(g) + 2B(g) ↔ 2C(g) ΔGo = −30.6 kJ. What is the value of ΔG in kJ at 25oC when the pressure of A is 1.3 atm, pressure of B is 1.5 atm, and the pressure of C is 3.7?
Calculate the equilibrium constant Keq for the following reaction at 25°C. (S° values in J/mol•K: N2(g),...
Calculate the equilibrium constant Keq for the following reaction at 25°C. (S° values in J/mol•K: N2(g), 191.5 ; O2(g), 205.0 ; Cl2(g), 223.0 ; NOCl(g), 261.6) N2(g) + O2(g) + Cl2(g) ↔ 2NOCl(g) ΔH° = 103.4 kJ a. 2.43 x 10−20 b. 8.82 x 10−29 c. 5.91 x 10−17 d. 2.01 x 10−10 e. 6.99 x 10−24
The activation energy for the reaction H2(g) + I2(g) --> 2HI(g) is changed from 184 kJ/mol...
The activation energy for the reaction H2(g) + I2(g) --> 2HI(g) is changed from 184 kJ/mol to 59.0 kJ/mol at 600 K by the introduction of a Pt catalyst. Calculate the value of the ratio rate(catalyzed)/rate(uncatalyzed). A) 1.00 B) 7.62 x 10^10 C) 1.38 D) 0.321 E) none of these I know the answer is B, But I want a detail solution.
Thermodynamics: Consider the equilibrium reaction A(g) + B(g) -><- C(g)+D(g). At T=298 K, the standard enthalpies...
Thermodynamics: Consider the equilibrium reaction A(g) + B(g) -><- C(g)+D(g). At T=298 K, the standard enthalpies of formation of the components in the gas phase are -20, -40, -30, and -10 kJ/mol for A,B,C, and D, respectively. The standard-state entropies of the components in the gas phase are 30, 50, 50, and 80 J/(mol K), in the same order. The vapor pressure of liquid C at this temperature is 0.1 bar, while all other components are volatile gases with Henry's...