An atom of rhodium (Rh) has a diameter of about 2.7×10−8cm.
What is the radius of a rhodium atom in angstroms (Å)?
r = |
1.4 |
Å |
What is the radius of a rhodium atom in meters (m)?
r = |
1.4×10−10 |
### How many Rh atoms would have to be placed side by side to
span a distance of 9.5 μm ?
Express your answer using two significant figures.
### If the atom is assumed to be a sphere, what is the volume in
m3 of a single Rh atom?
Express your answer using two significant figures.
(Hint: Do not use the rounded answer from Part A - use a radius
that has not been rounded to avoid introducing rounding error into
your calculation.)
Rh atom has diameter = 2.7 x 10^-8 cm
Rh radius = 2.7 x 10^-8/2 = 1.35 x 10^-8 cm
Rh radius in Angstrom = 1.35 Angstrom
Rh radius in meter = 1.35 x 10^-8 cm/100 = 1.35 x 10^-10 m
to cover distance of span = 9.5 um = 95,000 Angstrom
Number of Rh atoms needed = 95,000/2.7 = 35185.2 atoms
Volume of single Rh atom = (4/3).pi.r^3
= (4/3) x 3.14 x (1.35 x 10^-10)^3
= 1.03 x 10^-29 m^3
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