With the following data, estimate the half-life of an unknown, and suggest what isotope it is (see a table for a list of possible isotopes) (the correct answer is 1.82 h , argon-41. I just do not know how to get it. thank you)
time (s) | counting rate (counts/s) |
0 | 200 |
1000 | 182 |
2000 | 162 |
3000 | 144 |
4000 | 131 |
Let the concentration be C1 at time t1 and C2 at time t2
Then according to the equation we can write
------ (i)
------- (ii)
Divide equation 1 by equation 2 we get
Taking ln both sides we get
Now coming back to part (b) of the equation
b) Using the table we can write
Hence Lambda * No = 200
Now we can write the other equation
182 = 200 * e^(-1000*lambda)
ln(200/182) = 1000 * lambda
lambda = 9.431 * 10^(-5)
100 = 200 * e^(-t*9.431*10^(-5))
ln2 = t * 9.431 * 10^(-5)
t = 7348.21 seconds
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