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The reaction of the strong acid HBr with the strong base KOH is: HBr(aq) + KOH(aq)...

The reaction of the strong acid HBr with the strong base KOH is: HBr(aq) + KOH(aq) -->HOH(l)+KBr(aq).Compute the pH of the resulting solution if 6.0 × 101mL of 0.55M acid is mixed with 31mL of 0.42M base. Let\'s do this in steps: How many moles of acid before reaction? How many moles of base before reaction? What is the limiting reactant? How many moles of the excess reagent after reaction? What is the concentration of the excess reagent after reaction? What is the pH of the resulting solution?

Show all the work. Thank you.

  

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