Use the thermodynamic data provided below to determine ΔG (in
kJ/mol) for the vaporization of CaO at 91.8 °C if the initial
partial pressure of CaO is 1.76 atm. Report your answer to one
decimal place in standard notation (i.e. 123.4 kJ/mol).
Substance | ΔH°f (kJ/mol) | S° (J mol-1K-1) | ||
CaO (l) | -557.3 | 62.3 | ||
CaO (g) | 43.9 | 219.7 |
For CaO (l)
G = H - TS
G = -557.3 kJ/mol - 364.95 (0.0623kJ mol-1K-1)
G = -580.36 kJ mol-1
For CaO (l)
G = H - TS
G = 43.9 kJ mol-1- 364.95 (0.219.7kJ mol-1K-1)
G = 43.9 - 80.18
G = 36.28 kJ mol-1
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