Question

when 1907J of heat energy is added to 49.7g of ethanol C2H6O the temperature increases by 15.6 degrees Celsius calculate the molar heat capacity of C2H6O

Answer 1

q = m x C x DT

q = m x C x (T_f - T_i)

q = amount of heat energy gained or lost by substance

m = mass of sample = 49.7 g

C = heat capacity (J ^oC^-1 g^-1 or J K^-1 g^-1) = ?
T_f = final temperature
T_i = initial temperature Change in temperature = 15.6 degrees

Upon susbtituting the values in the above equation, we get

q = m x C x (T_f - T_i) imples 1907 J = 49.7 g x C x 15.6 degree

imples C = 1907 J/49.7 g x 15.6 Degree

    C = 1907 J / 775.32 g.^oC

C = 2.4596 J/g ^oC