1) The total number of π-bonds and closed rings in the molecular formula C11H12N2O2 is:
A) 4 |
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B) 5 |
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C) 6 |
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D) 7 |
ANSWER D) 7
The total number of π-bonds and closed rings in a compound is given by the INDEX OF HYDROGEN DEFICIENCY (IDH) of the molecule
Calculation of IDH
The molecular formula of the compound =C11H12N2O2
The molecular formula of the corresponding alkane =C11H24
In the calculation of the number of H atoms in the compound , ignore O atoms and for each N atom present reduce the number of H atom by 1.(If X, a halogen atom is presentthen for each halogen atom increase the number of H atoms by 1)
In the compound C11H12N2O2 there are 2 N atoms and 12 H atoms. The net number of H atoms =12-2=10
IDH = (Number of H atoms in the corresponding alkane - The number(net) of H atoms in the compound)/2
=(24 - 10)/2 =7
The total number of π-bonds and closed rings in the molecule = IDH = 7
ANSWER D) 7
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