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The reactant concentration in a second-order reaction was 0.110 M after 235 s and 2.70×10−2 M...

The reactant concentration in a second-order reaction was 0.110 M after 235 s and 2.70×10−2 M after 725 s . What is the rate constant for this reaction? Express your answer with the appropriate units. Include an asterisk to indicate a compound unit with multiplication, for example write a Newton-meter as N*m.

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Answer #1

The 2nd order rate constant is

k = (1/t) [1/At - 1/Ao]

Given that the reactant concentration in a second-order reaction was 0.110 M after 235 s and 2.70×10−2 M after 725 s .

Hence,

k = (1/235) [ 1/0.110 - 1/Ao] --------- Eq (1)   k =  (1/725) [ 1/0.027 - 1/Ao] ---------- Eq(2)

1/Ao = 1/0.11 - 235 k 1/Ao = 1/0.027 - 725k

Then,

1/0.11 - 235 k =  1/0.027 - 725k

490 k = 1/0.0027 -  1/0.11

k = 0.737 M-1 s-1

Therefore,

rate constant = 0.737 M-1 s-1

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