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A buffer is made with barbituric acid at 0.43M and its sodium salt at 0.18M. Set...

A buffer is made with barbituric acid at 0.43M and its sodium salt at 0.18M. Set up an equation to calculate the pH of the buffer. Ka for Barbituric acid is 1.05x10^-4

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Answer #1

Ka    = 1.05*10^-4

PKa   = -logKa

         = -log1.05*10^-4

         = 3.9788

[Acd]   = 0.43M

[Salt]   = 0.18M

PH   = PKa + log[Salt]/[Acid]

           = 3.9788 + log0.18/0.43

           = 3.9788-0.3782

            = 3.6006 >>>answer

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