A. The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as
k=Ae−Ea/RT
where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction.
However, a more practical form of this equation is
lnk2k1=EaR(1T1−1T2)
which is mathematically equivalent to
lnk1k2=EaR(1T2−1T1)
where k1 and k2 are the rate constants for a single reaction at two different absolute temperatures (T1 and T2).
Part 1: The activation energy of a certain reaction is 43.9 kJ/mol . At 28 ∘C , the rate constant is 0.0130s−1. At what temperature in degrees Celsius would this reaction go twice as fast?
Express your answer with the appropriate units.
Part 2: Given that the initial rate constant is 0.0130s−1 at an initial temperature of 28 ∘C , what would the rate constant be at a temperature of 100. ∘C for the same reaction described in Part A?
Express your answer with the appropriate units.
B. A reaction occurs by a two-step mechanism, shown below. Step 1: AX2(g) → AX(g) + X(g) Step 2: AX2(g) + X(g) → AX + X2(g) The intermediate in this reaction is ________, and the molecularity of the second step is ________. Enter your answers separated by a comma.
* The answer is NOT AX and 2
To
convert Kelvin to Celsius.
C+ 273= 313.4 K
Temperature in degree Celsius = 313.4 - 273 = 40.4 deg C
Please post the remaining question as a new question
Update
B)
A reaction intermediate is transient species within a multi-step reaction mechanism that is produced in the preceding step and consumed in a subsequent step to ultimately generate the final reaction product.
So X which is formed in Step 1 and consumed in step 2 to produce the product X2 is the intermediate.
Molecularity is the number of molecules that come together to react in an elementary reaction and is equal to the sum of stoichiometric coefficients of reactants in this elementary reaction.
Molecularity of the second step is 1+1= 2
The answer is X and 2
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