Question

What is the formula for copper(II) phosphate? Capitalization and punctuation count!

How many atoms of phosphorus are in 5.40 mol of copper(II) phosphate?

Answer 1

Formula of Copper(II)phosphate is Cu3(PO4)2

1 mol of copper(II)phosphate = 2 mol of P

then, 5.40 mol of copper(II)phosphate = 2*5.40 = 10.80 mol of P

therefore, number of atoms of phosphorous in 5.40 mol of copper(II)phosphate,

= 10.80 * 6.022*10²³                              since, 1 mol = Avagadro number = 6.022*10²³

= 6.504 * 10²⁴ atoms of P