Question

Consider the following three equilibria at 400°C: 2SO2(g)+O2(g)⇌2SO3(g)     Kp=.5*10^5 SO3(g)+H2O(g)⇌H2SO(g)    Kp=8.0*10^-1 2H2O(g)⇌2H2(g)+O2(g)        Kp=1.3*10^-33 What is...

Consider the following three equilibria at 400°C:

2SO2(g)+O2(g)⇌2SO3(g)     Kp=.5*10^5

SO3(g)+H2O(g)⇌H2SO(g)    Kp=8.0*10^-1

2H2O(g)⇌2H2(g)+O2(g)        Kp=1.3*10^-33

What is Kc at 400°C for the following equilibrium?

SO2(g)+O2(g)+H2(g)⇌H2SO4(g)

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Answer #1

1/2* (2SO2(g)+O2(g)⇌2SO3(g) ) Kp1 =.( 5*10^5)^(1/2)

SO3(g)+H2O(g)⇌H2SO4(g)            Kp2    = 8.0*10^-1

1/2* ( 2H2(g)+O2(g)   ⇌  2H2O(g) )    Kp3 =    (1/(1.3*10^(-33)))^(1/2)

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SO2(g)+O2(g)+H2(g)⇌H2SO4(g)            Kp = Kp1*kp2*kp3

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kp   = ( 5*10^5)^(1/2) *8.0*10^-1* (1/(1.3*10^(-33)))^(1/2) = 1.57*10^19

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