Question

# Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate...

Aqueous sulfuric acid

H2SO4

will react with solid sodium hydroxide

NaOH

to produce aqueous sodium sulfate

Na2SO4

and liquid water

H2O

. Suppose 71. g of sulfuric acid is mixed with 22.5 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Balanced equation is

H2SO4 + 2NaOH ------> Na2SO4 + 2H2O

number of moles of sulfuric acid = 71g / 98.079 g/mol = 0.724 mole

number of moles of NaOH = 22.5g / 40.0 g/mol = 0.5625 mole

from the balanced equation we can say that

1 mole of H2So4 requires 2 mole of NaOH so

0.724 mole of H2SO4 will require

= 0.724 mole of H2SO4 *(2 mole of NaOH / 1 mole of H2So4)

= 1.448 mole of NaOH

but we have only 0.5625 mole of NaOH which is the limiting reactant

from the balanced equation we can say that

2 mole of NaOH produces 2mole of H2O so

0.5625 mole of NaOH will produce 0.5625 mole of H2O

1 mole of H2O = 18.016g

0.5625 mole of H2O = 10.1 g

Therefore, the mass of H2O produced will be 10.1 g

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