Question

a. The standard enthalpy of vaporization of an inorganic compound is 38.9 kJ/mol. If the temperature...

a. The standard enthalpy of vaporization of an inorganic compound is 38.9 kJ/mol. If the temperature at which this phase change occurs is 221.72 °C, determine ΔS°vap (in J/mol/K) for this compound. Report your answer to three significant figures.

b. The entropy of freezing of an organic compound is -21.0 J/mol/K. If ΔH°freez is -14.01 kJ/mol, determine the temperature (in K) at which this phase change occurs. Report your answer to two decimal places

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Answer #1

(a). Standard enthalpy of vaporization, Hovap = 38.9 kJ/mol

= 38900 J/mol

Temperature = 221.72 oC = 494.87 K

Sovap = Hovap / T

= 38900 / 494.87

Sovap = 78.6 J/mol.K

(b). Sofus = - 21.0 J/mol.K

Hofus = -14.01 kJ/mol = - 14010 J/mol

Sofus = Hofus / T

T = - 14010 / - 21

= 667.14 K

Temperature =  667.14 K

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