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A student wants to perform the Fischer Esterification of pentanoic acid with 2-butanol.   For this reaction...

A student wants to perform the Fischer Esterification of pentanoic acid with 2-butanol.   For this reaction he/she wants to use a 3 molar excess of the alcohol. The student started the reaction with 5.25 mL of the alcohol. What is the volume (mL) of carboxylic acid needed for this reaction? Show all steps of your calculations.  

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Answer #1

M1V1 =M2V2

(given mass of 2-butanol/ molar mass of 2-butanol * 1/ volume of solution) * volume of alcohol (V1)  = (given mass of pentanoic acid / molar mass of pentanoic acid * 1/ volume of solution) * volume of pentanoic acid (V2)

taking density = mass / volume of solition we get

(Volume of 2-butanol) * (density of 2-butanol) * (1 mol of carboxylic acid / 3 mol of excess alcohol) x (molar mass of pentanoic acid / 1 mol of pentanoic acid) / (density of pentanoic acid)

(4.25 mL) x (0.808 g / 1 mL) x (1 mol / 3 mol) x (102.13 g / 1 mol) x ( 1 mL / .930 g) = 126 mL

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