Calculate the osmotic pressure in atm of a 3.85L aqueous solution containing 67.8g of MgCl2 at 22.00 oC.
MgCl2 (aq) --------------> Mg^2+ (aq) + 2Cl^- (aq)
no of particles i = 3
molarity = W/G.M.Wt* volume of solution in L
= 67.8/95*3.85 = 0.185M
T = 22 + 273 = 295K
=
iCRT
= 3*0.185*0.0821*295 = 13.45atm
>>>>>answer
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