Question

What will it's volume be if an additional 0.280 mol of gas is added to the cylinder? (Assume constant temperature and pressure.)

Answer 1

PV P V nT n T Because n1  n2 and P1  P2, 1 2 1 2  V V T T which is Charles' Law. The given information is tabulated below. Initial conditions Final Conditions T1  (88  273)K  361 K T2  ? V1  9.6 L V2  3.4 L The final temperature is given by: 1 2 2 1  T V T V (361 K)(3.4 L) (9.6 L)   2 2T 1.3 10 K 

PV P V nT n T 1 2 1 2  P P T T The given information is tabulated below. Initial conditions Final Conditions T1  (25  273)K  298 K T2  ? P1  0.800 atm P2  2.00 atm CHAPTER 5: GASES 97 The final temperature is given by: 1 2 2 1  T P T P (298 K)(2.00 atm) (0.800 atm) T2   745 K 472 C