Question

suppose that instead of collecting and recovering copper oxide in the experiment you had performed an additional copper reaction as follows CuO(s)+2HBr(aq)=CuBr2(aq)+H2O(l) What is the theoretical mass grams of copper (ll) bromide that you could form if you started with a mass of .33 grams of copper sphere?

Answer 1

Reaction for the formation of CuO from Cu is

2Cu(s) + O2(g) ----> 2 CuO(s)

Mass of Cu = 0.33 g, Atomic mass of Cu = 63.546 g/mol

Number of moles of Cu = 0.33 g/ 63.546 g/mol = 0.0052 mol

From reaction, number of moles of Cu reacted = number of moles of CuO formed so number of moles of CuO would formed = 0.0052 mol

From given reaction in question,

Number of moles of CuO reacted = number of moles of CuBr2 formed so number of moles of CuBr2 formed = 0.0052 mol

Molar mass of CuBr2 = 223.37 g/mol

Theoretical mass of CuBr2 = 0.0052 mol * 223.37 g/mol = 1.16 g