Question

What is the normality and molarity of 4.9% H2SO4?

Answer 1

Molarity = mol/L

Normality = #equivalent / L

#equivalent = mol*n

in this case H2SO4 = has 2 H+ ions ,thereofre n = 2

Normality will be twice as Molarity

then, let us calculate molarity

first; assume this is 4.9% by mass then

m = 100 g of solution

then

4.9 g are H2SO4

95.1 g are water

mol of H2SO4 = mass/MW = 4.9/98 = 0.05 mol of H2SO4 present

assume density of water is approx to 1 g/ml

therefore, 95.1 g = 95.1 ml = 0.0951 L

now, calculate M

M = mol/L = (0.05)/(0.0951) = 0.5257 mol of H2SO4 per liter

this has 2 equivalents so

N = 2*M = 2*0.5257 = 1.0514 N