Question

This question has 2 parts I figured out the answer to the first problem but don't understand the second part of the question... Please help and show answer and work thanks!

Question #1

A solution is prepared by dissolving 25.0 g of sucrose (C₁₂H₂₂O₁₁) in 377 g of H₂O. What is the molar mass of sucrose?

Answer- 342. g

Second part of question

What is the molality of m of that solution? answer in units of m. (this is the part I don't understand.)

Answer 1

Molality is a property of a solution and is defined as the number of moles of solute per kilogram of solvent.

Here , number of moles of sucrose = 25g/ 342 g/mol = 0.073 moles

Mass of Solvent H2O = 377g

Solvent in Kilograms = 0.377 kg

So, Molality = number of moles of solute/ kilogram of solvent

                   = 0.073 mole/ 0.377 kg

                   = 0.1936 mole/kg

                   = 0.1936 m