Question

How much heat must be supplied to a 500 g iron pan to increase its temperature from 20 OC to 100 OC. The specific heat of iron is c= 0.11 cal/g/OC

Answer #1

Heat change for a substance is given by q = c * m * T

c = specific heat of the substance; m = mass of the substance;
T =
T_{final} - T_{initial} , is the change in
temperature.

Given, c = 0.11cal/g/^{o}C
; m = 500g; Initial temperature
T_{initial} = 20^{o}C; Final temperature
T_{final} = 100^{o}C

Change in temperature, T =
T_{final} - T_{initial} = 100 - 20 =
80^{o}C

So, T =
80^{o}C

Substituting the values we get,

q = c * m * T = 0.11 * 500 * 80 = 4400 cal

q = 4400 cal

Therefore amount of heat to be supplied is **4400 cal or
4.4 kcal or 18.41 kJ** (since 1 cal =
4.184 J)

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NOTE
H2O (s) → H2O (l)
ΔH°fusion, water = 6.02 kJ/mol
Specific Heat Capacities:
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