Question

How much heat must be supplied to a 500 g iron pan to increase its temperature from 20 OC to 100 OC. The specific heat of iron is c= 0.11 cal/g/OC

Answer 1

Heat change for a substance is given by q = c * m * T

c = specific heat of the substance; m = mass of the substance; T = T_final - T_initial , is the change in temperature.

Given, c = 0.11cal/g/^oC   ;    m = 500g; Initial temperature T_initial = 20^oC; Final temperature T_final = 100^oC

Change in temperature, T = T_final - T_initial = 100 - 20 = 80^oC

So, T = 80^oC

Substituting the values we get,

q = c * m * T = 0.11 * 500 * 80 = 4400 cal

q = 4400 cal

Therefore amount of heat to be supplied is 4400 cal or 4.4 kcal or 18.41 kJ     (since 1 cal = 4.184 J)