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The enzyme hexokinase acts on both glucose and fructose. The Km and Vmax values are given...

The enzyme hexokinase acts on both glucose and fructose. The Km and Vmax values are given in the table. Using these data, compare and contrast the interaction of hexokinase with both of these substrates. Assume that [E]t is the same for both cases.

Substrate Km(M) Vmax(relative)
Glucose 1.0X10-4 1.0
Fructose 7.0X10-4 1.8
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Answer #1

This can be explained on the basis of Michaelis - Menten equation. In Michaelis - Menten equation, Km indicates the substrate concentration at which the reaction rate is half of the maxumum rate(Vmax) achieved by the system.

Hence lower the value of Km for a subtrate higher is the affinity of the enzyme towards the substrate. Here in the given data lower value of Km for glucose and higher value of Km for fructose indicates that hexokinase has higher affinity towards glucose in comparison to fructose.

How ever higher value of Vmax for fructose indicates that once the enzyme is bound to the subtrate it reacts more rapidly with fructose to form product.

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