Question

2) The dissociation constant for Fe(enterobactin)]3- at high pH is 10-49 M, a) Calculate the concentration...

2) The dissociation constant for Fe(enterobactin)]3- at high pH is 10-49 M,

a) Calculate the concentration of free Fe3+ in a 10 µM solution of Fe(enterobactin)]3-.

b) How many free iron ions are present in 1 L of such a solution?  

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Homework Answers

Answer #1

we can find out the concentration Fe3+

Fe(enterobactin)]3- --------> Fe3+ + (enterobactin)]6-

initail 10 m 0 0

equilibrium 10 m - x x x

or K disso = x2 /  10 m - x

10-49 M = x2 ( as 10 m is a small quantity and x in comparision to it is also very small therefore we neglect x in comparision to  10 m)

10-49 M * 10-5 = x2    ( 10 m  =10 * 10-6 = 105 as 1 m= 10-6M )

10-54 M =x2

or x= 10-27 there fore the concerntration of free Fe3+ =  10-27 M

2) there are twice the free ions present in solution having molarity   10-27 moles / litre  .

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