Aerosol cans have a label that warns the user not to use them above a certain temperature and not to dispose of them by incineration. Even an empty can contains residual gaseous propellant. For example, the residual pressure in a can is 1.51 atm when it is sitting on a shelf at 23 ∘C. If the can is placed on top of the furnace where the temperature reaches the boiling point of water, what is the pressure inside the can?
Since The volume of the can remains constant then
According to Lussac's Law, At constant volume , Pressure of a gas is directly proportional to the temperature.
i.e. P T
For two different conditions,
P1/P2 = T1/ T2
Now, given that, Initial Pressure (P1) = 1.51 atm
Initial temperature (T1) = 23 oC = 23 + 273.15 = 296.15 K
Final temperature (T2) = 100oC = 100 + 273.15 = 373.15 K
Thus, P2 = P1 * T2 / T1 = (1.51 atm * 373.15 K) /296.15 K = 1.90 atm
Hence, Pressure inside the can = 1.90 atm
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