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A .627g sample of a nonelectrolyte dissolves in 20.0g of cyclohexane. The solution freezes at 2.79...

A .627g sample of a nonelectrolyte dissolves in 20.0g of cyclohexane. The solution freezes at 2.79 degrees Celcius. The formula weight of the nonelectrolyte is 169.0 g/mol. Calculate the boiling point of the solution.

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Answer #1

molality   = W*1000/G.M.Wt*wweight of solvent in g

               = 0.627*1000/169*20    = 0.185m

kb = 2.79c/m

i =1

Tb   = i*Kb*m

            = 1*2.79*0.185

             = 0.516C0

boiling point = 80.74+0.516   = 81.256C0

       

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