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Part A: The activation energy of a certain reaction is 42.3 kJ/mol . At 29 ∘C...

Part A: The activation energy of a certain reaction is 42.3 kJ/mol . At 29 ∘C , the rate constant is 0.0170s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?

Part B: Given that the initial rate constant is 0.0170s−1 at an initial temperature of 29 ∘C , what would the rate constant be at a temperature of 120. ∘C for the same reaction described in Part A?

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