The sulfuric acid (98 g/mol) in a car battery has a density of 1.225 g/cm3 and is 3.75 M. What is the molality, mole fraction and percentage of sulfuric acid by mass in this solution?
Let the solution volume is 1.0L
3.75 M means that 3.75 moles of H2SO4
g H2SO4=3.75 mole x 98=367.5 g H2SO4.
Mass of solute
g solution=1.00L x 103 x 1.225g/ml = 1225 g solution
Mass of solutionMass of solvent = 1225-367.5 = 857.5g water
m= moles of solute / kg of solvent
= 3.75 moles/0.8575kg
= 4.37 m
% = g of solute / g of solution
= 367.5 g/ 1225 g
= 30%
XH2SO4 =3.75 mol H2SO4
(857.5g/18) mole H2O + 3.75 mol H2SO4
= 0.073
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