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for sake of this problem assume the reaction 1 is second order in H+. A solution...

for sake of this problem assume the reaction 1 is second order in H+. A solution containing ididie. thiousulfate starch and 2.5E-4 MH+ turns blue 14.7 second after hydrogen peroxide is added. how long will it take the same solution to turn if [H+] =1.25E-4M (all other quanities the same)?

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Answer #1

Given,

Rate of the reaction is second order wrt H+

=> Rate = K [H+]2

Initial Conc. of H+ = 2.5 E-4

Conc. of H+ for the second trial = 1.25 E-4

We see that the conc. of H+ is reduced to half in the second trial.

Since rate is proportional to the square of the conc. of H+, if the conc. of H+ is halved the rate is reduced to one fourth of the initial rate.

Therefore if initial rate is R, the rate of the reaction in second trial would be R/4.

If the rate is reduced to one quarter, the time taken will be 4 times

=> Time taken for the same solution to turn blue =14.7 x 4 = 58.8 sec

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