Question

A diving bell has an air space of 3.0 m' when on the deck of a boat.What is the volume of the air space when the bell has been lowered to a depth

of 50 m? Take the mean density of sea water to be 1.025 g cm-3 and assume that the temperature is the same as on the surface.

Answer 1

Solution :-

Air space = 3.0 m3

Depth = 50 m * 3.28084 feet / 1 m = 164 feet

1 atm = 33.9 feet

So 164 feet * 1 atm / 33.9 feet = 4.84 atm

Final pressure = 1 atm + 4.84 atm = 5.84 atm

Now we have initial volume that is 3 m3 and initial pressure that is 1 atm and final pressure so using these values we can calculate the final volume

P1V1 = P2V2

V2 = P1V1/P2

     = 1 atm * 3 m3 / 5.84 atm

    = 0.51 m3

So the final air space is 0.51 m3