Question

Sodium hydroxide (NaOH) has a lattice energy of -887 kJ/mol and a heat of hydration of -932 kJ/mol. How much solution could be heated to boiling by the heat evolved by the dissolution of 28.0 g of NaOH? (For the solution, assume a heat capacity of 4.0 J/g⋅∘C, an initial temperature of 25.0 ∘C, a boiling point of 100.0 ∘C, and a density of 1.05 g/mL.)

Answer #1

We need to consider

a) Heat evolved due to dissolution of NaOH

b) Heat required to boil the solution

Let us calculate heat evolved in dissolution of NaOH

Heat of dissolution = Heat of hydration - Lattice energy = -932 - (-887) = -45 KJ / moles

The amount of NaOH dissolved = 28 grams

Molecular weight of NaOH = 40 g / mole

So Heat of dissolution = -45 X 28 / 40 = 31.5 KJ

Now let us calculate heat required

Heat requried = Mass X Heat capacity of solution X change in temprature

Heat utilized = Heat given

31.5 X 10^3 Joules = Mass X 4 X 75

Mass = 105 grams

Density = 1.05 g / mL

so volume which will be heated = Mass / Density = 105 / 1.05 = 100mL

Sodium nitrate has a lattice energy of -2.48 x 10^2 kJ/mol, and
a heat of hydration of -234 kJ/mol.
Determine how much heat is evolved or absorbed when 16.5 g of
sodium nitrate completely dissolves in water?

Potassium perchlorate (KClO4) has a lattice energy of -599
kJ/mol and a heat of hydration of -548 kJ/mol.
A) Find the heat of solution for potassium perchlorate when 10.2
g of potassium perchlorate is dissolved with enough water to make
118.5 mLof solution.

Lattice energy for LiF(s) = -1047 kJ/mol
Enthalpy of hydration for Li+(g) = -536 kJ/mol
Enthalpy of hydration for F–(g) = -502 kJ/mol
Determine the enthalpy of solution for LiF(s), using the data
provided.

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol. How much potassium
nitrate (in kg) has to dissolve in water to absorb 100 kJ of
heat?

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol. How much potassium nitrate
has to dissolve in water to absorb 102 kJ of heat? There are 4.184
kJ/kcal. Also note the answer is to be reported in kg.

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol.
Question:
How much potassium nitrate has to dissolve in water to absorb
109 kJ of heat? There are 4.184 kJ/kcal. Also note the answer is to
be reported in kg.

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol
1.How much potassium nitrate has to dissolve in water to absorb
107 kJ of heat? There are 4.184 kJ/kcal. Also note the answer is to
be reported in kg.

A. Sodium metal reacts with water to produce hydrogen gas and
sodium hydroxide according to the chemical equation shown below.
When 0.020 mol of Na is added to 100.00 g of water, the temperature
of the resulting solution rises from 25.00°C to 33.60°C. If the
specific heat of the solution is 4.18 J/(g • °C), calculate
ΔH for the reaction, as written.
2 Na(s) + 2 H2O(l) → 2 NaOH(aq) +
H2(g) ΔH= ?
Sodium metal reacts with water to...

Potassium nitrate has a lattice energy of -163.8
kcal/mol and a heat of hydration of -155.5 kcal/mol.
How much potassium nitrate has to dissolve in water to absorb
104 kJ of heat?
Express your answer using two significant figures.
Answer in kg

Potassium nitrate has
a lattice energy of -163.8 kcal/mol and a heat of hydration of
-155.5 kcal/mol. How much potassium nitrate has to dissolve in
water to absorb 1.00x102 kJ of heat?
Provide your
answer: numberE^n, remember to watch for sig. figs.

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