If neon travels at 400 m/s, what is the velocity of C4H10 at the same temperature?
Velocity of C4H10 = 235.7 m/s
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According to Graham's law of effusion gas molecule move from high concentration to low concentration, and the velocity of gas particle depend on the mass. i.e. the ratio of velocities of two gases are inversely propotional to square root of the molar mass
Given by the following relation, i.e. v1/v2 = sqrt[m2/m1]
v1 and v2 are velocities, and m1 and m2 are molar masses.
Neon, v1 = 400 m/s, Neon, m1 = 20.18 g/mol
C4H10, v2 = ?, C4H10, m2 = 58.12 g/mol
so, v2 = v1/sqrt[m2/m1] = 400 / sqrt[58.12/20.18] = 400/1.697 = 235.7 m/s
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