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Initially 5 mole of nitrogen are at a temperature of 25. Degrees C and a pressure...

  1. Initially 5 mole of nitrogen are at a temperature of 25. Degrees C and a pressure of 10.0 bar. Cv,m=20.8 J K-1 mol-1 and is independent of temperature. Suppose the pressure is suddenly dropped to 1.00 bar. Calculate the final temperature, U, q, w, and H. State any assumptions that you make

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Answer #1

we consider the process as an isothermal . t1=t2=298 K t2-t1 = 0

U= H =0 since the internal energy of an ideal gas is a function of temperature only and as temperature is kept constant , the internal energy of system remain constant .

q= -w =-(- 2.303 nRT log P1/P2) H = (U + PV) = U + (PV)

= 2.303 *5*8.314 * 298 log 10 = U + (nRT) as T = constant

= 28529.24 J     H = 0+0 = 0

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