Question

Calculate deltaS for N2 (1 bar, 298 K) --> N2 (32 bar, 1500 K). Assume N2...

Calculate deltaS for N2 (1 bar, 298 K) --> N2 (32 bar, 1500 K). Assume N2 to be an ideal gas. CP = 28.58 + 3.77 x 10-3 T – 0.50 x 105 T-2 J K-1 mol-1

Homework Answers

Answer #1

For n moles of ideal gas,

     

n =? (not given in question)

Let us take , n=1, for 1 mole of Ideal gas

Here, T1 = 298 K, P1 =1 bar, T2 =1500 K, P2 = 32 bar, R = 8.314 JK-1 mol-1,

CP = 28.58 + 3.77 x 10-3 T – 0.50 x 105 T-2 J K-1 mol-1 (Cp value is not clear).

Substituing the values of Cp, T2, T1, P1 and P2 in the equation below, we can get the value of S. Since Cp value looks strange

  

S = Cp ln (1500/298) -8.314 ln (32/1)

= Cp ln (5.0335) - 8.314 x ln (32)

=Cp x 1.616 - 28.814

Putting a correct value of Cp we can get S.

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