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A 10.0 L container contains 1.0 L of solution of a gas. Assume [gas] = 1.5...

A 10.0 L container contains 1.0 L of solution of a gas. Assume [gas] = 1.5 x 10^-4 M in solution when 2 mol of gas remains in gas form. If 1 mol of gas is removed from the gas phase, what will be the new concentration of the gas in the solution? What is the value of k? c = kP

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Answer #1

In case of dissolution of gas in liquid Gas Gas in solution

Equilibrium Constant (Kc) = [Gas]/[Gas in solution]

[Gas in solution] = 1.5 x 10-4 M

  [Gas] = 2/9 (2 mole of gas occupies remaining 9 L of empty space of the container)

= 2.2 x 10-1 M

Kc   = (1.5 x 10-4 M)/(2.2 x 10-1 M)

= 6.8 x 10-4

[Gas] after removal of 1 mole of Gas from container = 1/9

= 1.1 x 10-1 M

[Gas in solution] after removal of 1 mole of Gas from container = Kc x [Gas]

= (6.8 x 10-4) x (1.1 x 10-1 M)

= 7.5 x 10-5 M

In this case concentration of the gas is praportional to the pressure of the gas

Kc = Kp

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