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A + 2 B ⇌ C What are the equilibrium concentrations of A, B and C...

A + 2 B ⇌ C What are the equilibrium concentrations of A, B and C if 2.6 mol A and 2.6 mol B are added to a 1.0 L flask? Assume that the equilibrium constant for this reaction is Kc = 1.7x10^15.

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Answer #1

A +       2 B <----------------> C

2.6mol         2.6 mol                         0

2.6-x              2.6-2x                        x

Kc = [C] / [A] [B]^2

1.7 x 10^15 = x / (2.6-x)(2.6 - 2x)^2

1.7 x 10^15 = x / (2.6 - x) (4x^2 - 10.4x + 6.76)

1.7 x 10^15 = x / (2.6 - x) (4x^2 - 10.4x + 6.76)

by solving the above equation :

x = 1.30

equilibrium concentrations :

[A] = 1.3 M

[B] = 0.0 M

[C] = 1.3 M

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