Question

For a different reaction, Kc = 7.22×106, kf=4.13×105s−1, and kr= 5.72×10−2 s−1 . Adding a catalyst increases the forward rate constant to 7.35×107 s−1 . What is the new value of the reverse reaction constant, kr, after adding catalyst?

Answer 1

For a bidirectional or reversible reaction, the system attains equilibrium when the rate of forward reactiopn and reverse reaction becomes equal. Adding a catalyst decreases the activation energy and enhances the rate of the reaction without participating in any way in the reaction and comes out as it is. In case of an equilibrium, adding a catalyst enhances the rate of reaction of both forward as well as reverse reaction. Thus, adding a catalyst if increases the forward rate constant to 7.35×107 s⁻¹, the reverse reaction constant, kr, after adding catalyst will be also 7.35×107 s⁻¹.