Calculate EOCell for the following examples:
a) Fe(s) | Fe2+(0.10 M) | | Cu2+(0.10 M) | Cu(s)
b) F2(g) + 2Cl-(aq) --> 2F-(aq) + Cl2(g)
c) For the combination of a Zn/Zn2+ couple and a Ag|AgCl(s) | Cl-(aq) couple
Eocell means the standard reduction potenial of cell which is equal to the difference in cathodic reduction potenial minus anodic reduction potential of cell.
a.In this case Eored(Fe2+)=-0.44 and Eored(Cu2+)=0.16
Thus Eocell= Eored(Cu2+)- Eored(Fe2+)=0.16-(-0.44)=0.6 volts.
b..
Eored(F2)=2.87 volts and Eored(Cl2)=1.36
thus, Eocell= Eored(F2)-Eored(Cl2)=2.87-1.36=1.51 volts.
c.
Eored(Zn2+)=-0.76 colts and Eored(Ag/AgCl)=0.22 v
Thus,
, Eocell=Eored(Ag/AgCl)-Eored(Zn2+)=0.22-(-0.76)=0.98 Volts
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