A photon is emitted from a hydrogen atom when an electron goes from the n = 6 to the n = 2 state. What kind of electromagnetic radiation is this? Select one:
a. Visible Light
b. Ultraviolet Light
c. Infrared Radiation
d. X-Ray Radiation
e. Microwave Radiation
Solution: When an elctron jump from ni =6 to nf =2
Then for the transition for ni=6 to nf =2, by using the Rydberg equation.
1/ λ=R x (1/nf2−1/ni2)
where λ is the wavelength of the emittted photon
and R is the Rydberg constant, which is equal to 1.097x107 m−1
On putting the values,
1/λ=1.097x107 m−1x (1/22−1/62)
1/ λ=2.4378x106 m−1 hence,
λ=4.10 x10−7m = 410 nm
So, you know that when an electron falls from ni=6 to nf=2, a photon of wavelength 410 nm is emitted and this range of wavelength is shown by Visible light (400- 700 nm).
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