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A three-step process for producing molten iron metal from Fe2O3 is: 3Fe2O3 + CO → 2Fe3O4...

A three-step process for producing molten iron metal from Fe2O3 is:

3Fe2O3 + CO → 2Fe3O4 + CO2

Fe3O4 + CO → 3FeO + CO2

FeO + CO → Fe + CO2

Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 67.7%, 94.0% and 55.5%, what mass of iron metal would be produced from 250. kg of Fe2O3?

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Answer #1

250Kg of Fe2O3 (MW=159.7g/mol)

From each reaction

Yield 67.7%

Yield 94%

Yield=55.5%

MW of Fe 55.85g/mol

61.76kg Fe

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