Question

What volume of 12.0 moles nitric acid is required to prepare 6.11 L of 0.100 moles nitric acid ? A)0.196 B)19.6 c)0.611 d)0.0509 e) 1.96

What volume of 18.0 mole so forecast said is required to prepare 28.2 L of 0.126 mole. H2So4

A)5.07 B)0.197 C)508 D)3.55 E) 224

103.8 g sample nitric acid solution that is 70% HNO3 (by mass) contains A 72.7 B 1.15 C 1.65 D 5.27 E none of these

Answer 1

1)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 12 M

M2 = 0.1 M

V2 = 6.11 L

use:

M1*V1 = M2*V2

V1 = (M2 * V2) / M1

V1 = (0.1*6.11)/12

V1 = 0.0509 L

Answer: d

2)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 18 M

M2 = 0.126 M

V2 = 28.2 L

use:

M1*V1 = M2*V2

V1 = (M2 * V2) / M1

V1 = (0.126*28.2)/18

V1 = 0.197 L

Answer: B

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