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**PLEASE SHOW WORK. THANKS** The following equilibrium, 2 NO(g) + 3F2(g) ⇌ 2 F3NO (g), is...

**PLEASE SHOW WORK. THANKS**

The following equilibrium, 2 NO(g) + 3F2(g) ⇌ 2 F3NO (g), is established by adding 0.20 mol of NO and 0.30 mol of F2 into a 5.0 L container. If y moles of F3NO (g) are present at equilibrium, how many moles of F2 are present at equilibrium? (Answer: [F2] = 0.30 – 3y/2)

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Answer #1

I: NO = 0.2 mol

F2 = 0.3

F3NO = 0

EQ: NO =

F2 =

F3NO = y

as

I did this because as you know, we have y number of moles, which mean a part of F2 converted to Y, we use stoichiometry to calculate the remaining F2 moles

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