Question

to resolve an object in an electron microscope the wavelength of the electrons must be close...

to resolve an object in an electron microscope the wavelength of the electrons must be close to the diameter of the object. What kinetic energy must the electrons have in order to resolve a protein molecule that is 4.40 nm in diameter? take the mass of an electron to be 9.11x10^-31kg.

Homework Answers

Answer #1

Expression of De Broglie wavelength can be written as follows:

λ = h / mv

Where, λ = De Broglie wavelength = 4.40nm = 4.40 x 10-9 m

h = Plank’s constant = 6.626 x 10-34 J.s

m = mass of electron = 9.11 x 10-31 kg

v = velocity of electron

Thus, v can be calculated as shown below:

v = h / mλ

v = (6.626 x 10-34 J.s) / (9.11 x 10-31 kg)( 4.40 x 10-9 m)

v = 0.1653 x 106 m/s

Expression for kinetic energy can be shown as follows:

Kinetic energy = 1/2 m v2

Kinetic energy = 1/2 (9.11 x 10-31 kg) (0.1653 x 106 m/s)2

Kinetic energy = 0.12446 x 10-19 kg.m2/s2

Kinetic energy = 0.12446 x 10-19 J

Thus, in order to resolve given protein molecule electron should have 0.12446 x 10-19 J kinetic energy.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
To resolve an object in an electron microscope, the wavelength of the electrons must be close...
To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. What kinetic energy must the electrons have in order to resolve a protein molecule that is 2.70 nm in diameter? Take the mass of an electron to be 9.11x10-31kg.
To resolve an object in an electron microscope, the wavelength of the electrons must be close...
To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. What kinetic energy must the electrons have in order to resolve a protein molecule that is 6.60 nm in diameter? Take the mass of an electron to be 9.11× 10−31 kg
To resolve an object in an electron microscope, the wavelength of the electrons must be close...
To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. What kinetic energy must the electrons have in order to resolve a protein molecule that is 5.80 nm in diameter? Take the mass of an electron to be 9.11× 10–31 kg.
An electron beam in which electrons have a wavelength of 2.4pm is used in an electron...
An electron beam in which electrons have a wavelength of 2.4pm is used in an electron microscope with an aperture diameter of 2mm. (a) What is the angular resolution of this microscope, i.e. what is the minimum angle, in radians, that can be resolved? (b) Compare your answer in part (a) to the resolution achieved with visible light with wavelength of 550nm. (c) Compute the wavelength of photons with the same kinetic energy as the electrons and comment on why...
An electron microscope is designed to resolve objects as small as 135 pm, about the size...
An electron microscope is designed to resolve objects as small as 135 pm, about the size of a gold atom. What energy electrons must be used in this microscope? I've seen people use the size of the object as the wavelength, I want to know why ? and some poeple use E=hc/lamda and others use E=h^2/2m(lamda)^2, why? help would be much appreciated.
An electron microscope accelerates electrons from rest through a potential difference of 10 kV. The charge...
An electron microscope accelerates electrons from rest through a potential difference of 10 kV. The charge on an electron is -1.60×10-19C and the mass of an electron is 9.11×10-31kg. (a) If the potential energy of an electron is taken to be 0 initially (at a 0 V plate), what potential energy does it have in Joules after accelerating to the 10 kV plate? (The electrons actually pass through a small hole in this plate before continuing on toward the sample)....
The resolving power of a microscope is proportional to the wavelength used. A resolution of 1.0  10-11...
The resolving power of a microscope is proportional to the wavelength used. A resolution of 1.0  10-11 m (0.010 nm) would be required in order to "see" an atom. (a) If electrons were used (electron microscope), what minimum kinetic energy would be required for the electrons? keV (classically) keV (relativistically) (b) If photons were used, what minimum photon energy would be needed to obtain 1.0  10-11 m resolution? keV
a) In an electron microscope, a potential difference of 20 kV is applied to accelerate the...
a) In an electron microscope, a potential difference of 20 kV is applied to accelerate the electrons. Determine the wavelength (in m) of the X-ray photons of equal energy as said electrons. If the wavelength of the X-rays is between 10 and 0.01 nm, what can you deduce about its calculation? b) An electron and a neutron have the same wavelength of de Broglie.
The electron microscope can "see" smaller detail than an optical microscope because the wavelength of the...
The electron microscope can "see" smaller detail than an optical microscope because the wavelength of the electron can be made much shorter than visible light. Now consider the possibility of a proton microscope. By what potential difference (in volts) must A) a proton and B) an electron be accelerated to give a wavelength of 5x10-12m? Can you think of a reason why we have electron microscopes, but do not commonly have proton microscopes?
How fast must an electron move to have a kinetic energy equal to the photon energy...
How fast must an electron move to have a kinetic energy equal to the photon energy of light at wavelength 578 nm? The mass of an electron is 9.109 × 10-31 kg.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT