Question

If 5.34 g of Fe are reacted with 500 mL of 0.500 M H2SO4, what volume, in liters, of hydrogen gas would be collected at 25.0o C and 1.00 atm?

Answer 1

Fe + H2SO4 --------> FeSO4 + H2

moles of H2SO4 reacted = 0.500 x 500/1000 = 0.25

moles of Fe = 5.34 / 55.84 = 0.096 moles

according to balanced reaction

1 mole Fe reacts with 1 mole H2SO4

0.096 moles Fe reacts with 0.096 x 1 / 1 = 0.096 moles H2SO4

we have exess H2SO4

so Fe is limiting reagent.

1 mole Fe gives 1 mole H2

0.096 moles Fe gives 0.096 x 1 / 1 = 0.096 moles H2

convert moles to volume

PV = nRT

V = nRT / P

V = 0.096 x 0.0821 x 298 / 1.0

V =2.35 L H2