Question

. The equilibrium constant for the following reaction in groundwater is about 1.5x10-56. If the initial...

. The equilibrium constant for the following reaction in groundwater is about 1.5x10-56. If the initial concentration of K+ was 12 mM and of H2 (aq) was 0.10 mM, what are the equilibrium concentrations expected? The equilibrium constant is very small, so you can assume x is small.

2 K+ (aq) + H2 (aq) ⇌ 2 K (aq) + 2 H+ (aq)

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Answer #1

    2 K+ (aq) + H2 (aq) ⇌ 2 K (aq) + 2 H+ (aq)

Initial      12mM       0.10mM       0              0

Final      (12-2x)mM (0.10-x)     2x            2x

Concentration of 2H+ = Concentration of 2K = 3.662 * 10^(-16) M

Concentration of K+ = 12mM(approximately)

Concentration of H2 = 0.1mM(approximately)

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