reaction taking place is:
2Al3+ + 3Sn ----> 2Al + 3Sn2+
number of electron = 6
Eo (Sn2+/Sn) = -0.14 V
Eo (Al3+/Al) = -1.66 V
Eo cell = Eo (right) - Eo (left)
= -1.66 - (-0.14)
= -1.52 V
use:
E cell = Eo cell - 0.059/n * log {[Sn2+]^3 / [Al3+]^2}
= -1.52 - 0.059/6 * log
{(0.01)^3 / (0.002)^2}
= -1.52 +5.92*10^-3
= -1.514
Answer: cell potential = -1.514 V
delta G = -n*F*Ecell
=
-6*96500*(-1.514)
=8.77*10^5 J
Since delta G is positive it is Electrolytic cell
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