Consider the following reaction: 3CH4 + 2H2O + CO2 --> 4CO + 8H2 If the rate of disappearance of CO2 is 7.4 M/s, match the remaining compounds with their respective rates of appearance or dissapearance.
CH4, H2O, CO, H2
Answer: According to the question , here the equation is :
3CH4 + 2H2O + CO2 --> 4CO + 8H2
Here , -1/3 d[CH4] /dt = -1/2 d[H2O]/dt = -d[CO2]/dt = 1/4 d[CO]/dt = 1/8 d[H2]/dt
And we have , -d[CO2]/dt = 7.4 m/s
so , - d[CH4]/dt = 7.4 * 3 = 22.5 [ Means option [C] ]
for , -d[H2O]/dt = 7.4 * 2 = 14.8 means approx 15 [ hence option [B]
for , d[CO]/dt = 7.4 *4 = 29.6 means approx 30 , hence option [D] .
Now, for , d[H2]/dt = 7.4 * 8 = 59.2 means approx 60 hence option [A] .
So it is all about the given question . Thank you :)
Get Answers For Free
Most questions answered within 1 hours.