Question

Consider the following reaction: 3CH4 + 2H2O + CO2 --> 4CO + 8H2 If the rate of disappearance of CO2 is 7.4 M/s, match the remaining compounds with their respective rates of appearance or dissapearance.

CH_4, H₂O, CO, H₂

A.60

B.15

C.22.5

D.30

Answer 1

Answer: According to the question , here the equation is :

  3CH4 + 2H2O + CO2 --> 4CO + 8H2

Here , -1/3 d[CH4] /dt = -1/2 d[H2O]/dt = -d[CO2]/dt = 1/4 d[CO]/dt = 1/8 d[H2]/dt

And we have , -d[CO2]/dt = 7.4 m/s

so , - d[CH4]/dt = 7.4 * 3 = 22.5 [ Means option [C] ]

for , -d[H2O]/dt = 7.4 * 2 = 14.8 means approx 15 [ hence option [B]

for , d[CO]/dt = 7.4 *4 = 29.6 means approx 30 , hence option [D] .

Now, for , d[H2]/dt = 7.4 * 8 = 59.2 means approx 60 hence option [A] .

So it is all about the given question . Thank you :)