The experimentally determined rate law for the reaction
2NO(g)+2H2(g)→N2(g)+2H2O(g) is
rate=k[NO]2[H2].
Part A
What are the reaction orders in this rate law?
Enter your answers numerically separated by commas.
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nNO, nH2 = |
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Part B
Would the reaction rate increase more if we double the concentration of NO or the concentration of H2?
A) The reaction rate will increase more if we double the concentration of NO. | |
B) The reaction rate will increase more if we double the concentration of H2. | |
C) The effect of doubling the concentration of NO will be the same as the effect of doubling the concentration of H2. |
Part A
Total Order of the reaction = (2+1) = 3
nNO = 2
nH2 = 1
Part B
The rate law depends on the square of the concentration of NO and proportional to H2 concetration
The reaction rate will increase more if we double the concentration of NO
Hence the correct answer is Option A
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