Question

The decomposition reaction given below: 2 IF5(g) 1 I2(g) + 5 F2(g) is carried out in a closed reaction vessel. If the partial pressure of IF5(g) is decreasing at the rate of 144 torr/min, what is the rate of change of the total pressure in the vessel? Delta Ptot /delta t = ___torr/min

Answer #1

From the balanced reaction

**2IF _{5(g)} ------> I_{2(g)} +
5F_{2(g)}**

It is given that

Partial pressure of IF_{5}(g) is decreasing at the rate
of 144 torr/min

Since moles ratio of IF5 and F2 is 2:5

The increase in the partial pressure of 5mol F2 =

rate of increase partial pressure of F2 = 360 torr/min

Since mole ratio of I2 and IF5 = 1:2

Rate of increase of pertial pressure of I2 =

=72 torr/min

**So sum of partial pressure increasing rate = 360 + 72 =
432 torr/min**

**But 2mol IF5 is partial pressure rate is
decreasing**

**so we have to subtract it from the above
sum**

**Rate of change of total partial pressure = 432 - 144 =
288 torr/min**

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