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A silver block, initially at 55.0 ∘C, is submerged into 100.0 g of water at 25.2...

A silver block, initially at 55.0 ∘C, is submerged into 100.0 g of water at 25.2 ∘C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.8 ∘C. What is the mass of the silver block?

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Answer #1

heat lost by silver = heat gained by water

heat gained by water = mCpdT

                              = 100 x 4.184 x (27.8 - 25.2)

                              = 1087.84 J

So, heat lost by solver = 1087.84 J

1087.84 = m x 0.233 x (55 - 27.8)

mass of silver block = m = 171.65 g

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