Question

CuSo4 * 5 H20 originally weighting 1.158 grams is heated and then weights .819 What is...

CuSo4 * 5 H20 originally weighting 1.158 grams is heated and then weights .819

What is the reaction equation of this heating process?

How many waters did your hydration lose?

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Homework Answers

Answer #1

The formula weight of CuSO4.5H2O is

Cu: 1 x 63.546 = 63.546 amu

S: 1 x 32.065 = 32.065 amu

O: 9 x 15.9994 = 143.9946 amu

H: 10 x 1.0079 = 10.079 amu

Formula weight of CuSO4.5H2O = 249.6846 amu

Formula weight of H2O = 18 amu

Formula weight of 5 molecules of H2O = 18 x5 = 90 amu

Five H2O weight percentage in CuSO4.5H2O = 36%

One H2O molecule weight percentage in CuSO4.5H2O = 36/5 = 7%

CuSO4 weight percentage in CuSO4.5H2O = 64%

CuSO4.5H2O originally weighting = 1.158 gms

After heating weight = 0.819 gms

Weight loss = 1.158 – 0.819 = 0.339 gms

How much percentage weight lost?

1.158gms -------100%

Then 0.339gms ----- ??%

= (0.339 x 100)/1.158 = 29.27% weight lost

One water molecule weight is 7%

So total (29.27)/7 = 4 water molecules lost in hydration process

Final formula = CuSO4.H2O

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