CuSo4 * 5 H20 originally weighting 1.158 grams is heated and then weights .819
What is the reaction equation of this heating process?
How many waters did your hydration lose?
The formula weight of CuSO4.5H2O is
Cu: 1 x 63.546 = 63.546 amu
S: 1 x 32.065 = 32.065 amu
O: 9 x 15.9994 = 143.9946 amu
H: 10 x 1.0079 = 10.079 amu
Formula weight of CuSO4.5H2O = 249.6846 amu
Formula weight of H2O = 18 amu
Formula weight of 5 molecules of H2O = 18 x5 = 90 amu
Five H2O weight percentage in CuSO4.5H2O = 36%
One H2O molecule weight percentage in CuSO4.5H2O = 36/5 = 7%
CuSO4 weight percentage in CuSO4.5H2O = 64%
CuSO4.5H2O originally weighting = 1.158 gms
After heating weight = 0.819 gms
Weight loss = 1.158 – 0.819 = 0.339 gms
How much percentage weight lost?
1.158gms -------100%
Then 0.339gms ----- ??%
= (0.339 x 100)/1.158 = 29.27% weight lost
One water molecule weight is 7%
So total (29.27)/7 = 4 water molecules lost in hydration process
Final formula = CuSO4.H2O
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